102 CHEMISTRY AND TECHNOLOGY OF EXPLOSIVES
Nitrolic acids (II) are relatively stable when R is alkyl but can lose nitrous
acid with furoxane (IV) formation (Wieland and Semper [14]). Aci-nitroparaffins (III)
readily yield aldehydes when R is alkyl. At lower temperatures the product
V (R=C 6 H 5 ) predominates.
According to Ponzio [35], benzaldoxime can form phenyl-gem-dinitromethane
C 6 H 5 CH(NO 2 ) 2 , under the action of N 2 O 4.
NITRATION WITH NITROGEN DIOXIDE IN THE PRESENCE
OF SULPHURIC ACID
Pinck [88] studied the nitrating action of nitrogen dioxide in a sulphuric acid
solution. According to this author, the nitrating action of the solution proceeds
as follows, from each N 2 O 4 molecule with the formation of one molecule of HNO 3
and one of nitrosylsulphuric acid:
(27)
When treating 1 mole of toluene with 1.05 mole of N 2 O 4 in the presence of
1.6 moles of 95 % sulphuric acid at 50-55°C for 3½ hr, the yield of nitrotoluene
obtained amounted to 87.5% of theory.
According to Battegay [58], nitration with nitrogen dioxide in the presence
of sulphuric acid followed a course such that an addition product of H 2 SO 4 and
the aromatic hydrocarbon was formed initially. Battegay assumed the sulphuric
acid activated the aromatic ring in a way similar to the role of aluminium or fer-
ric chlorides in the Friedel-Crafts reaction, or as in a chlorination reaction. Indeed,
Battegay found that benzene may be readily chlorinated in the presence of sul-
phuric acid instead of FeCl 3.
Benzene activated with sulphuric acid would add on to N 2 O 4 which, according
to Battegay, has the structure of “nitrosyl nitrate” NO 2 .ONO. An addition prod-
uct was thought to be formed which, in the presence of an excess of sulphuric
acid, would decompose to yield a nitro compound and nitrosylsulphuric acid.
C 6 H 6 + NO 2 + H 2 SO 4 -> C 6 H 5 NO 2 +NSO 5 H + H 2 O (28)
Titov and his co-workers [34] proposed the following mechanism of nitra-
tion of aromatic compounds with nitrogen dioxide in the presence of sulphuric
acid:
RH + N 2 O 4 -> RNO 2 + HNO 2
N 2 O 4 + H 2 SO 4 <-> HNO 3 + NSO 5 H
2NSO 5 H + H 2 O <-> N 2 O 3 + 2H 2 SO 4
(a)
(b)
(c)