Thermodynamics and Chemistry

(Kiana) #1

APPENDIXI ANSWERS TOSELECTEDPROBLEMS 508


9.5 (a)xN 2 D8:83 10 ^6
xO 2 D4:65 10 ^6
yN 2 D0:763
yO 2 D0:205
(b)xN 2 D9:85 10 ^6
xO 2 D2:65 10 ^6
yN 2 D0:851
yO 2 D0:117
9.7(b)fAD0:03167bar,fAD0:03040bar
9.8 (a)In the mixture of composition
xAD0:9782, the activity coefficient is

(^) B11:5.
9.9(d)kH,A 680 kPa
9.11Values formB=mD 20 : (^) AD1:026,
(^) m;B D 0:526; the limiting
slopes are d (^) A=d.mB=m/D 0 ,
d (^) m;B=d.mB=m/D0:09
9.13pN 2 D0:235bar
yN 2 D0:815
pO 2 D0:0532bar
yO 2 D0:185
pD0:288bar
9.14(b)hD1:2m
9.15(a)p.7:20cm/p.6:95cm/D1:2bar
(b)MBD 187 kg mol^1
mass binding ratioD1:37
10.2 D0:392
11.1ÅrHD63:94kJ mol^1
KD4:41 10 ^2
11.2(b)ÅfH: no change
ÅfS: subtract0:219J K^1 mol^1
ÅfG: add 65 J mol^1
11.3p.298:15K/D2:6 10 ^6 bar
p.273:15K/D2:7 10 ^7 bar
11.4(a)240:34kJ mol^1 ,470:36kJ mol^1 ,
230:02kJ mol^1
(b)465:43kJ mol^1
(c)39:82kJ mol^1
11.5ÅHD0:92kJ
11.6LAD0:405J mol^1
LBD0:810kJ mol^1
11.7 (a)State 1:
nC 6 H 14 D7:822 10 ^3 mol
nH 2 OD0:05560mol
amount of O 2 consumed:0:07431mol
State 2:
nH 2 OD0:11035mol
nCO 2 D0:04693mol
mass of H 2 O=1:9880g
(b)Vm(C 6 H 14 )D131:61cm^3 mol^1
Vm(H 2 O)D18:070cm^3 mol^1
(c)State 1:V(C 6 H 14 )D1:029cm^3
V(H 2 O)D1:005cm^3
VgD348:0cm^3
State 2:
V(H 2 O)D1:994cm^3
VgD348:0cm^3
(d)State 1:
nO 2 D0:429mol
State 2:
nO 2 D0:355mol
yO 2 D0:883
yCO 2 D0:117
(e)State 2:
p 2 D27:9bar
pO 2 D24:6bar
pCO 2 D3:26bar
(f)fH 2 O.0:03169bar/D0:03164bar
State 1:fH 2 OD0:03234bar
State 2:fH 2 OD0:03229bar
(g)State 1:
H 2 OD0:925
O 2 D0:981
fO 2 D29:4bar
State 2:
H 2 OD0:896
O 2 D0:983
CO 2 D0:910
fO 2 D24:2bar
fCO 2 D2:97bar
(h)State 1:
ngH 2 OD5:00 10 ^4 mol
nlH 2 OD0:05510mol
State 2:ngH 2 OD5:19 10 ^4 mol
nlH 2 OD0:10983mol

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