Reduction formulae 429
Problem 6.∫ Use a reduction formula to determine
x^3 sinxdx.
Using equation (3),
∫
x^3 sinxdx=I 3
=−x^3 cosx+ 3 x^2 sinx− 3 ( 2 )I 1
and I 1 =−x^1 cosx+ 1 x^0 sinx
=−xcosx+sinx
Hence
∫
x^3 sinxdx=−x^3 cosx+ 3 x^2 sinx
−6[−xcosx+sinx]
=−x^3 cosx+ 3 x^2 sinx
+ 6 xcosx−6sinx+c
Problem 7. Evaluate
∫ π
2
0
3 θ^4 sinθdθ, correct to 2
decimal places.
From equation (3),
In=[−xncosx+nxn−^1 (sinx)]
π
2
0 −n(n−^1 )In−^2
=
[(
−
(π
2
)n
cos
π
2
+n
(π
2
)n− 1
sin
π
2
)
−( 0 )
]
−n(n− 1 )In− 2
=n
(π
2
)n− 1
−n(n− 1 )In− 2
Hence
∫ π
2
0
3 θ^4 sinθdθ= 3
∫ π
2
0
θ^4 sinθdθ
= 3 I 4
= 3
[
4
(π
2
) 3
− 4 ( 3 )I 2
]
I 2 = 2
(π
2
) 1
− 2 ( 1 )I 0 and
I 0 =
∫ π
2
0
θ^0 sinθdθ=[−cosx]
π
2
0
=[− 0 −(− 1 )]= 1
Hence
3
∫π 2
0
θ^4 sinθdθ
= 3 I 4
= 3
[
4
(π
2
) 3
− 4 ( 3 )
{
2
(π
2
) 1
− 2 ( 1 )I 0
}]
= 3
[
4
(π
2
) 3
− 4 ( 3 )
{
2
(π
2
) 1
− 2 ( 1 )( 1 )
}]
= 3
[
4
(π
2
) 3
− 24
(π
2
) 1
+ 24
]
= 3 ( 15. 503 − 37. 699 + 24 )
= 3 ( 1. 8039 )= 5. 41
Now try the following exercise
Exercise 170 Further problems on
reduction formulae for integrals of the form∫
xncosxdxand
∫
xnsinxdx
- Use a reduction formula to determine∫
x^5 cosx⎡dx.
⎢
⎣
x^5 sinx+ 5 x^4 cosx− 20 x^3 sinx
− 60 x^2 cosx+ 120 xsinx
+120cosx+c
⎤
⎥
⎦
- Evaluate
∫π
0 x
(^5) cosxdx, correct to 2 decimal
places. [−134.87]
- Use a reduction formula to determine∫
x^5 sin⎡xdx.
⎢
⎣
−x^5 cosx+ 5 x^4 sinx+ 20 x^3 cosx
− 60 x^2 sinx− 120 xcosx
+120sinx+c
⎤
⎥
⎦
- Evaluate
∫π
0 x
(^5) sinxdx, correct to 2 decimal
places. [62.89]
44.4 Using reduction formulae for
integrals of the form
∫
sinnxdx
and
∫
cosnxdx
(a)
∫
sinnxdx
LetIn=
∫
sinnxdx≡
∫
sinn−^1 xsinxdxfrom laws of
indices.
Usingintegrationbyparts,letu=sinn−^1 x,fromwhich,