50 Higher Engineering Mathematics
In the series expansion for shx,letx= 2 θ, then:sh2θ= 2 θ+( 2 θ)^3
3!+( 2 θ)^5
5!+···= 2 θ+4
3θ^3 +4
15θ^5 +···Hencech(
θ
2)
−sh2θ=(
2 +θ^2
4+θ^4
192+···)−(
2 θ+4
3θ^3 +4
15θ^5 +···)= 2 − 2 θ+θ^2
4−4
3θ^3 +θ^4
192−4
15θ^5 +···as far the term inθ^5Now try the following exerciseExercise 23 Further problems on series
expansions for coshxand sinhx- Use the series expansion for chxto evaluate,
correct to 4 decimal places: (a) ch 1.5(b)ch0. 8
[(a) 2.3524 (b) 1.3374]
2. Use the series expansion for shx to evalu-
ate, correct to 4 decimal places: (a) sh0. 5
(b) sh2
[(a) 0.5211 (b) 3.6269]
3. Expand the following as a power series as far
as the term inx^5 :(a)sh3x(b) ch2x
⎡
⎢
⎣
(a) 3x+9
2x^3 +81
40x^5(b) 1+ 2 x^2 +2
3x^4⎤
⎥
⎦In Problems 4 and 5, prove the given identities,
the series being taken as far as the term inθ^5
only.- sh2θ−shθ≡θ+
7
6θ^3 +31
120θ^5- 2sh
θ
2−chθ
2≡− 1 +θ−θ^2
8+θ^3
24−θ^4
384+θ^5
1920