76 Higher Engineering Mathematics
Hence lim
x→ 0
{
x−sinx
x−tanx
}
=−
1
2
Now try the following exercise
Exercise 34 Further problems on limiting
values
Determine the following limiting values
- lim
x→ 1
{
x^3 − 2 x+ 1
2 x^3 + 3 x− 5
}[
1
9
]
- lim
x→ 0
{
sinx
x
}
[1]
- lim
x→ 0
{
ln( 1 +x)
x
}
[1]
- lim
x→ 0
{
x^2 −sin3x
3 x+x^2
}
[−1]
- lim
θ→ 0
{
sinθ−θcosθ
θ^3
}[
1
3
]
- lim
t→ 1
{
lnt
t^2 − 1
}[
1
2
]
- lim
x→ 0
{
sinhx−sinx
x^3
}[
1
3
]
- lim
θ→π 2
{
sinθ− 1
lnsinθ
}
[1]
- lim
t→ 0
{
sect− 1
tsint
}[
1
2
]