CHAP. 6: THERMODYNAMICS OF HOMOGENEOUS MIXTURES [CONTENTS] 147
Solution
Substituting into (6.36) and (6.39) gives∆solHethanol =− 980
0. 1
=− 9800 J mol−^1.∆HM =− 9800
4. 9 / 0 .1 + 1
=− 196 J mol−^1.Note:Itis important to point out that the enthalpy of mixing ∆HMrelates to one mole
of a mixture while the heat of solution relates to one mole of a solute.