4.6. WEAK INTERACTION THEORY 241
Hence, we deduce from (4.6.35) and (4.6.36) that81
(
ρw
ρn) 6
g^2 w=8
√
2
(
mw
mp) 2
× 10 −^5 ̄hc.Then we derive the relation(4.6.37) g^2 w=8
81
√
2
(
mw
mp) 2
× 10 −^5 ×
(
ρn
ρw) 6
̄hc.In a comparison with (4.5.66) and (4.6.37), we find that the strong chargegsand the weak
chargegwhave the same magnitude order. Direct computation shows thatg^2 w
g^2 s≃ 0. 35 equivalentlygw
gs≃ 0. 6.
4.6.4 PID mechanism of spontaneous symmetry breaking
In the derivation of equations (4.6.7) and (4.6.8) we have used the PID mechanism of sponta-
neous symmetry breaking. In this subsection we shall discuss the intermediate vector bosons
W±,Zand their dual scalar bosonsH±,H^0 , called the Higgs particles by using the PID mech-
anism of spontaneous symmetry breaking.
We know that the interaction field equations are oriented toward two directions: i) to
derive interaction forces, and ii) to describe the field particles and derive the particle transition
probability. The PID-PRI weak interaction field equations describing field particles are given
by (4.4.42)-(4.4.45). Here, for convenience, we write them again as follows:
∂νWν μa −gw
̄hcεbcagα βWα μbWβc−gwJμa= (∂μ−1
4
(mHc
̄h) 2
xμ+gw
̄hc(4.6.38) γbWμb)φa,−∂μ∂μφa+(m
Hc
h ̄) 2
φa−
gw
̄hc(4.6.39) γb∂μ(Wμbφa)=
gw
̄hcεbcagα β∂μ(Wα μbWβc)+gw∂μJaμ−1
4
(
mHc
h ̄)^2 xμ∂μφa,wheremHis the Higgs particle mass, andWμa( 1 ≤a≤ 3 )describe the intermediate vector
bosons as follows(4.6.40)
W±: Wμ^1 ±iWμ^2 ,
Z: Wμ^3 ,andφadescribe the dual Higgs bosons as(4.6.41)
H±: φ^1 ±iφ^2 ,
H^0 : φ^3.By (4.4.46), equations (4.6.38)-(4.6.39) need to be supplemented with three gauge fixing
equations. According to physical requirement, we take these equations as(4.6.42) ∂μWμa= 0 for 1≤a≤ 3.