7.3. BLACK HOLES 441
whereRis the object radius,Rsis the radius of the black hole,ρis the mass density outside
the core, and
(7.3.36) Mr=Mb+
∫r
Rs
4 πr^2 ρdr.
SinceRs≪R, we takeRs=0 in the integrals (7.3.35) and (7.3.36). We assume that the
densityρis a constant. Then, it follows from (7.3.35) and (7.3.36) that
V=− 4 πGρ
∫R
0
[
Mbr+
4 π
3
ρr^4
]
dr=− 4 πGρ
(
MbR^2
2
+
4 π
3 × 5
ρR^5
)
.
Byρ=M 1 /^43 πR^3 andMb=M−M 1 ,we have
(7.3.37) V=−
G
R
(
3
2
MM 1 −
9
10
M^21
)
.
The stability of the object requires that−Vtakes its maximum at someM 1 such that
dV/dM 1 =0. Hence we derive from (7.3.37) that
(7.3.38) M 1 =
5
6
M, Mb=
1
6
M.
The relation (7.3.38) means that a black hole with massMbcan form an astronomical object
with massM= 6 Mb.
3.Relation between radius and temperature.A black hole with massMbdetermines the
massMof the corresponding astronomical system:M= 6 Mb. Then, by the Jeans relation
(7.3.33), the radiusRand average temperatureTsatisfy
(7.3.39) T=
2 × 6 GmMb
5 kR
whereTis expressed as
T=
3
4 πR^3
∫
BR
τ(x)dx,
whereBRis the ball of this system, andτ(x)is the temperature distribution. Letτ=τ(r)
depend only onr, then we have
(7.3.40) T=
3
R^3
∫R
0
r^2 τ(r)dr.
4.Solar system.For the Sun,M= 2 × 1030 kg andR= 7 × 108 m. Hence the mass of the
solar black hole core is about
M⊙b=
1
3
× 1030 kg,
and the average temperature has an upper limit:
T=
4
5
×
6. 7 × 10 −^11 m^3 /kg·s^2 × 1030 kg× 1. 7 × 10 −^27 kg
1. 4 × 10 −^24 kg·m^2 /s^2 ·K× 7 × 108 m