2.5. PRINCIPLE OF LAGRANGIAN DYNAMICS (PLD) 85
By (2.5.23), we have
∇L=e
c∇~A·v+e∇A 0.Thanks to
∇~A·v=∇(~A·v) (by∂v= 0 )
=(~A·∇)v+ (v·∇)~A+v×curl~A+~Acurlv
=(v·∇)~A+v×curl~A,the equation (2.5.25) reads
(2.5.26)
dP
dt+
e
cd~A
dt=
e
c(v·∇)~A+e
cv×curl~A+e∇A 0.It is known that
d~A
dt
=
∂~A
∂t+
∂~A
∂xkdxk
dt=
∂~A
∂t+ (v·∇)~A.Hence (2.5.26) is rewritten as
(2.5.27)
dP
dt
=−
e
c∂~A
∂t+e∇A 0 +
e
cv×curl~A.Then, by (2.5.20), the equation (2.5.27) takes the form
dP
dt
=eE+e
c
v×curl~A.Thus, we have deduced (2.5.21) from the action (2.5.23).
Now, we deduce the Einstein energy-momentum formula for the4-dimensional energy-
momentum under an electromagnetic field. Corresponding to the least action principle of
classical mechanics, the momentumPand energyEof a charged particle are given by
(2.5.28) P=
∂L
∂v, E=v·∂L
∂v−L.
By (2.5.23), we refer from (2.5.28) that
(2.5.29)
P=
mv
√
1 −v^2 /c^2+
e
c~A, ~Athe magnetic potential,E=
mc^2
√
1 −v^2 /c^2+eA 0 , A 0 the electric potential.It follows from (2.5.29) that
(2.5.30) (E−eA 0 )^2 =c^2 (~P−
e
c
~A)^2 +m^2 c^4 ,which is the Einstein energy-momentum relation under with an electromagnetic field.
It is the formula (2.5.30) that makes us to take the energy and momentum operators in
quantum mechanics in the following form:
(2.5.31) ih ̄
∂
∂t−eA 0 , −ih ̄∇−c
e~A,
which were also given in (2.2.52). In particular, the particular form of (2.5.31) leads to the
origin of gauge theory.