12—Tensors 367
But,
~u. 11 T(~v) =uieˆi.vj^11 T(~ei)
=uivjˆei.(Tkjˆek)
=uivjTij.
The last step comes from the orthonormality of theˆe’s. Becauseuiandvjare arbitrary, this shows that
Tij=^02 T(ˆei,ˆej) (23)
This is the equation that makes the transformation of bases simple. If you want to computeTij′ this is
Tij′ =^02 T(ˆe′i,ˆe′j)
Each of theˆe′iis expressible In terms of theˆei. For example
T 11 ′ =^02 T(ˆe′ 1 ,ˆe′ 1 ) =^02 T
(
eˆ 1 +ˆe 2
√
2
,
ˆe 1 +eˆ 2
√
2
)
Use linearity in each of the variables, and you get
T 11 ′ =
1
2
[ 0
2 T(ˆe^1 ,ˆe^1 ) +
0
2 T(ˆe^1 ,ˆe^2 ) +
0
2 T(ˆe^2 ,ˆe^1 ) +
0
2 T(eˆ^2 ,ˆe^2 )
]
=
1
2
[
T 11 +T 12 +T 21 +T 22
]
This is the same result as in Eq. ( 21 ), and it equals 3/2. Another case would beT 12 ′
T 12 ′ =^02 T(ˆe′ 1 ,ˆe′ 2 ) =^02 T
(
ˆe 1 +ˆe 2
√
2
,
eˆ 2 −ˆe 1
√
2
)
=
1
2
[
T 12 −T 11 +T 22 −T 21
]
,
with the same results as before.