GTBL042-19 GTBL042-Callister-v2 September 13, 2007 13:59
Revised Pages19.8 Transmission • 771And, finally, solving forβ, realizing thatIT′/I 0 ′=0.98 andx=200 mm, yieldsβ=−1
xln(
IT′
I′ 0
)
=−
1
200 mmln(0.98)= 1. 01 × 10 −^4 mm−^1Concept Check 19.5Are the elemental semiconductors silicon and germanium transparent to visible
light? Why or why not?Hint:you may want to consult Table 12.3.[The answer may be found at http://www.wiley.com/college/callister (Student Companion Site).]19.8 TRANSMISSION
The phenomena of absorption, reflection, and transmission may be applied to the
passage of light through a transparent solid, as shown in Figure 19.7. For an incident
beam of intensityI 0 that impinges on the front surface of a specimen of thicknessl
and absorption coefficientβ, the transmitted intensity at the back faceITis
Intensity of radiation
transmitted through
a specimen of
thicknessl,
accounting for all
absorption and
reflection lossesIT=I 0 (1−R)^2 e−βl (19.19)whereRis the reflectance; for this expression, it is assumed that the same medium
exists outside both front and back faces. The derivation of Equation 19.19 is left as a
homework problem.
Thus, the fraction of incident light that is transmitted through a transparent
material depends on the losses that are incurred by absorption and reflection. Again,
the sum of the reflectivityR, absorptivityA, and transmissivityT, is unity accordinglIncident beam
Transmitted beam
IT = I 0 (1 – R)^2 e – lI 0Reflected beam
IR = I 0 RFigure 19.7 The transmission of light through a transparent medium for which there is
reflection at front and back faces, as well as absorption within the medium. (Adapted from
R. M. Rose, L. A. Shepard, and J. Wulff,The Structure and Properties of Materials,Vol. IV,
Electronic Properties.Copyright©c1966 by John Wiley & Sons, New York. Reprinted by
permission of John Wiley & Sons, Inc.)