- 1,350 – 337.5πsquare units. The area of ΔABO is A = (^12 )(b)(h) =
(^12 )(60)(45) = 1,350. Subtract the area of the slice of circle found in
question 381 from 1,350 to get the area of the shaded region:
1,350 – 337.5πsquare units. - 147 πin^2 .The area of the larger circle with the radius of 14 is
π(14)^2 or 196πin^2. The area of the smaller circle with the radius
of 7 is π(7)^2 or 49πin^2. Subtract these two areas to find the area of
the outer ring: 196π– 49π= 147πin^2. - 18.4πin^2 .As found in the previous question, the area of the outer
ring is 147πin^2. Since the shaded region is defined by a 45º angle
and 34650 ºº= ^18 , multiply 147πby ^18 to get 18.4πin^2. - 1.75πinches.The circumference of small O is 14πinches. A 45°
slice of that circumference is one-eighth the circumference, or
1.75πinches. - 3.5πinches.The circumference of concentric O is 28πinches.
An eighth of that circumference is 3.5πinches. - Arc CD is twice as long as arc AB.
This shows that just because two arcs are defined by the same
angle, they will not necessarily have the same arc length. If the
angle measurement is the same, the bigger the radius of the circle,
the bigger the arc length.
Set 80
- Area= 48 square feet.Use the Pythagorean theorem to find AG.
(4 2 )^2 = (4)^2 + b^2. 32 = 16 + b^2 .b= 4. If AGequals 4 feet, then
AF,EFand BDequal 8 feet, and AEequals 16 feet. The area of a
trapezoid is half its height times the sum ^12 of its bases: ^12 (4 ft.)(8 ft.
+ 16 ft.) = 2(24) = 48 square feet.501 Geometry Questions