501 Geometry Questions

(Jacob Rumans) #1

  1. Acute equilateral triangle KLM. When all three codes are
    congruent, you have an equilateral triangle.


Set 24



  1. 59°.180° – (m∠C + m∠A) = m∠B. 180° – 121° = m∠B. 59° = m∠B

  2. 30°.180° – (m∠R + m∠Q) = m∠S. 180° – 150° = m∠S. 30° = m∠S

  3. 30°.Step One: 180° – 60° = m∠T. 120° = m∠T. Step Two: 180° –
    m∠T = m∠U + m∠V. 180° – 120° = m∠U + m∠V. 60° = m∠U +
    m∠V. Step Three: 60° shared by two congruent base angles equals
    two 30° angles.

  4. 156°.180° – (m∠F + m∠G) = m∠E. 180° – 24° = m∠E. 156° = m∠E

  5. No.The sum of the measurements of ∠B and ∠C equals 75°.
    Subtract 75° from 180°, and ∠A measures 105°. ΔABC cannot be
    acute if any of its interior angles measure 90° or more.


Set 25



  1. c.Choice ais not an acute triangle because it has one right angle.
    In choice b, the sum of interior angle measures exceeds 180°.
    Choice dsuffers the reverse problem; its sum does not make 180°.
    Though choice cdescribes an equilateral triangle; it also describes
    an isosceles triangle.

  2. d. Choice ais not an obtuse triangle; it is a right triangle. In choice
    band choice cthe sum of the interior angle measures exceeds 180°.

  3. d.A right triangle has a right angle and two acute angles; it does
    not have any obtuse angles.

  4. d.Angles and sides are measured in different units. 60 inches is not
    the same as 60°.

  5. c.Let m∠A = 2x, m∠B = xand m∠C = x. 2 x+ x+ x= 180°.
    4 x= 180°. x= 45°.


501 Geometry Questions
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