1.6
=0.9711 atm −0.00576 atm =0.965 atm1.7
1.8
1.9
1.10
Since the total is 3.45 mol, and the total pressure is 1 atm, the partial
pressures are given by:1.11 Cell membranes are largely lipids but they also have steroids, pro-
teins, and sugars.1.12 The lipids are arranged in a bilayer, with the hydrophobic chains in
the interior and the polar groups on the exterior.1.13 The fluid-mosaic model states that the components of a membrane
are free to move within the membrane.p().
.
Argon.mol
mol==atm atm0 033
345
1001
p().
.
Oxygen.
mol
mol==atm atm0 725
345
1021
p().
.
Nitrogen.mol
mol==atm atm269
345
1078
n().
.Argon.g
gmol==0 013 − mol100
39 9
1 0 033
n().
.Oxygen.
g
gmol==0 232 − mol100
32 0
1 0 725
n().
.Nitrogen.g
gmol==0 755 − mol100
28 0
1 269
V
T
V
T
initial TT
initialnal
nal=→=nal in
3
33 iitialnal
initialV
V
⎛ 3
⎝
⎜⎜
⎞
⎠
⎟⎟=()
.
.
298
09
1
K
L
00
283
L
K
⎛
⎝
⎜⎜
⎞
⎠
⎟⎟=
nPV
RT
()()
(.
==
× −
12
821 10^2
atm L
L atm/(K mol)))( ).
283
0 086
K
= molP
nRT
V(. )(. ))( )
==
×
01 831 298
10
mol J/(K mol K
.
10− 33 =24 8
mkPaP
.
..
=
×
×
− ×
2448 5
24 96 10
1
(^33) 101 10 5
J
matm
Paa−0 00576atm.=
−
( )(. ))( )
(.
1 8 3 298
25 0 043
mol J/(K mol K
LLmol−−− −−⎛
⎝
⎜⎜
⎞
⎠
1 21 2 ⎟
1
360
1
)( ) 25
.
molLatm mol
mol
L⎟⎟2P
nRT
Vnban
V=
−
−
⎛
⎝
⎜⎜
⎞
⎠
⎟⎟
2440 ANSWERS TO PROBLEMS
9781405124362_5_end.qxd 4/29/08 9:17 Page 440