(c)9.21 (a)(b)(c)9.22 (a)(b)(c)9.23 (a)−iZ∇
(b)x
(c) (−iZ∇)^2 =−Z^2 ∇^29.24 (a)(b)(c)9.25 (a)(b)(c)9.26 (a)=Eψ(x,y,z)−++
⎛
⎝
⎜⎜
⎞
⎠
⎟⎟
Z^22
22
22
2 mx y z^2 xyz∂
∂
∂
∂
∂
∂
ψ(),, ++++()()Ax By Czψx y z,,−+
⎛
⎝
⎜⎜
⎞
⎠
⎟⎟ +
Z^22
22
2 mx y^2 xy Axy x∂
∂
∂
∂
ψψ()( )(,,,,yExy)()= ψ−+
⎛
⎝
⎜⎜
⎞
⎠
⎟⎟ ++
Z^22
22
2 mx y^2 xy Ax By∂
∂
∂
∂
ψ()(,^33 )( )ψψxy,,=E xy( )−+
⎛
⎝
⎜⎜
⎞
⎠
⎟⎟ ++
Z^22
22
23
2 mx yxy Ax B∂
∂
∂
∂
ψ()(, yyxy Exy)( )ψψ,,= ( )−++=
Z^22
22
2 mxxAxBxxEx
d
dψψψ() ( ) () ()−+=
Z^22
22
2 mxxAxxEx
d
dψψψ() ( ) () ()−+=
Z^22
2 mx^2 xAxxExd
dψψψ() ( ) () ()Δ
Δ
x
m.
()(
==
×
×
−
−Z
2 9
105 10
2 5 10 10
34
3Js
kg −−−=×−
6111 10^26
msm
).
Δ
Δ
x
m.
()(
==
×
×
−
−Z
2 9
105 10
2 5 10 10
34
3Js
kg −−−=×−
2111 10^30
msm
).
Δ
Δ
x
m.
()(
==
×
×
−
−Z
2 9
105 10
2 5 10 10
34
3Js
kg −−−=×−
1111 10^31
msm
).
Δ
Δ
x
m.
(.
==
×
×
−
−Z
2 9
105 10
2 9 11 10
34
31Js
kg))( ).
10
−− 71 =576 3
msmΔ
Δ
x
m.
(.
==
×
×
−
−Z
2 9
105 10
2 9 11 10
34
31Js
kg))( ),
10
−− 10 1 =576 300
msmΔ
Δ
x
m.
(.
==
×
×
−
−Z
2 9
105 10
2 9 11 10
34
31Js
kg))( ),
10
−− 91 =57 630
msmΔ
Δ
x
m.
(.
==
×
×
−
−Z
2 9
105 10
2 1 67 10
34
27Js
kg))( ).
10
−− 71 =0 314
msmANSWERS TO PROBLEMS 457
9781405124362_5_end.qxd 4/29/08 9:17 Page 457