214 COMPUTER AIDED ENGINEERING DESIGN
Figure 7.7 (a) Example of a quadratic-cubic Bézier surface with control polynet and (b) change in
patch’s shape with relocation of two control points
xx x x
yy y y
zz z z
x
y
z
z
pupxp
pup p
pup p
= 0
- 1.5 0 3
- 1 2 0
- 0.75 0 0
v = 0 = 0.75
v
⇒⇒
Also, at u = 0.5, v = 0.5
rr
rrr
u
uu u
= {0, 2, 0}; = {3, 0, 0}
= {0, 0, 0} = {0, 0, 0} = {0, 0, – 6}
v
vvv
⇒ G 11 = 4, G 12 = 0, G 22 = 9; L = M = 0, N = 6
K LN M
GG G
= = –
- 12 = 0
2
11 22 122
κκ H GN G L GM
GG G
=^1
2
( + ) =
+ – 2
2( – )
=^1
(^123)
11 22 12
11 22 12
κκ 2
⇒ κ 1 =^2
3
,κ 2 = 0
Hence, the radius of curvature (at rp) = 1/κ 1 = 1.5 and since the Gaussian curvature K = 0, the surface
is developable.
For control points r 10 and r 13 changed as (0, 1, 0.5) and (3, 1, 0.5) respectively, lifting them up by
0.5 units each along the z-direction, the new equation of the surface is
r( , ) = [(1 – ) 2 (1 – ) ]
(0, 0, 0) (1, 0, 1) (2, 0, 1) (3, 0, 0)
(0, 1, 0.5) (1, 1, 1) (2, 1, 1) (3, 1, 0.5)
(0, 2, 0) (1, 2, 1) (2, 2, 1) (3, 2, 0)
(1 – )
3 (1 – )
3 (1 – )
22
3
2
2
3
uuuuuv
v
vv
vv
v
⎡
⎣
⎢
⎢
⎢
⎤
⎦
⎥
⎥
⎥
⎡
⎣
⎢
⎢
⎢
⎢
⎢
⎤
⎦
⎥
⎥
⎥
⎥
⎥
The new shape of the surface is shown in Figure 7.7(b).
1
0.5
0
3
2
1
0 0 1
2
3
4
z
y x
1
0.5
0
z
3
2
1
0 0 1
2 3
4
x
y
(a) (b)