222 COMPUTER AIDED ENGINEERING DESIGN
⇒ r 3 (u, 0) = φ 0 (u)P 00 + φ 1 (u)P 10 + φ 2 (u)s 0 (0) + φ 3 (u)s 1 (0) (7.40a)
r(u, 1) = φ 0 (1)b 0 (u) + φ 1 (1)b 1 (u) + φ 2 (1)t 0 (u) + φ 3 (1)t 1 (u)
+φ 0 (u)a 0 (1) + φ 1 (u)a 1 (1) + φ 2 (u)s 0 (1) + φ 3 (u)s 1 (1) –r 3 (u, 1) = b 1 (u)
⇒ r 3 (u, 1) = φ 0 (u)P 01 + φ 1 (u)P 11 + φ 2 (u)s 0 (1) + φ 3 (u)s 1 (1) (7.40b)
Now,
∂
∂v
r(u,v) = ∂
∂v
r 1 (u,v) + ∂
∂v
r 2 (u,v)–∂
∂v
r 3 (u,v)
= ∂
∂v
φ 0 (v)b 0 (u) + ∂
∂v
φ 1 (v)b 1 (u) + ∂
∂v
φ 2 (v)t 0 (u) + ∂
∂v
φ 3 (v)t 1 (u)
+φ 0 (u) ∂
∂v
a 0 (v) + φ 1 (u) ∂
∂v
a 1 (v) + φ 2 (u) ∂
∂v
s 0 (v)
+φ 3 (u) ∂
∂v
s 1 (v)–∂
∂v
r 3 (u,v) (7.41)
The twist vectors χχχχχij, initially introduced in section 7.1.1, are the mixed derivatives defined as
ij ui j i j j ui
u
u
u
= ( , ) = ( ) = ( ) ui j, = 0, 1; = 0, 1
2
=, = = =
∂
∂∂
∂
∂
∂
v ∂
v
v
rstvvv (7.42)
Thus, for v = 0, realizing from Figure 7.15 that ∂
∂v
a 0 (0) = t (0) and ∂
∂v
a 1 (0) = t 0 (1), Eq. (7.41)
becomes
∂
∂v
r(u, 0) = t 0 (u) + φ 0 (u)t 0 (0) + φ 1 (u)t 0 (1) + φ 2 (u)χχχχχ 00 + φ 3 (u)χχχχχ 10 – ∂
∂v
r 3 (u, 0)
=t 0 (u)
⇒ ∂
∂v
r 3 (u, 0) = φ 0 (u)t 0 (0) + φ 1 (u)t 0 (1) + φ 2 (u)χχχχχ 00 + φ 3 (u)χχχχχ 10 (7.43a)
Similarly, for v = 1, noting that ∂
∂v
a 0 (1) = t 1 (0) and ∂
∂v
a 1 (1) = t 1 (1),
∂
∂v
r(u, 1) = t 1 (u) + φ 0 (u)t 1 (0) + φ 1 (u)t 1 (1) + φ 2 (u)χχχχχ 01 + φ 3 (u)χχχχχ 11 – ∂
∂v
r 3 (u, 1)
=t 1 (u)
⇒ ∂
∂v
r 3 (u, 1) = φ 0 (u)t 1 (0) + φ 1 (u)t 1 (1) + φ 2 (u)χχχχχ 01 + φ 3 (u)χχχχχ 11 (7.43b)
From Eqs. (7.40) and (7.43), we can use bi-cubic lofting with respect to v to get the corrected surface,
that is
r 3 (u,v) = φ 0 (v)r 3 (u, 0) + φ 1 (v)r 3 (u, 1) + φ 2 (v) ∂
∂v
r 3 (u, 0) + φ 3 (v) ∂
∂v
r 3 (u, 1)
or r 3 (u,v) = φ 0 (v) [φ 0 (u)P 00 + φ 1 (u)P 10 + φ 2 (u)s 0 (0) + φ 3 (u)s 1 (0)]
+φ 1 (v) [φ 0 (u)P 01 + φ 1 (u)P 11 + φ 2 (u)s 0 (1) + φ 3 (u)s 1 (1)]
+φ 2 (v) [φ 0 (u)t 0 (0) + φ 1 (u)t 0 (1) + φ 2 (u)χχχχχ 00 + φ 3 (u)χχχχχ 10 ]
+φ 3 (v) [φ 0 (u)t 1 (0) + φ 1 (u)t 1 (1) + φ 2 (u)χχχχχ 01 + φ 3 (u)χχχχχ 11 ]