Chapter 11 Electron Transfer and Electrochemistry
Example 11.4
Write the anode and cathode half-reactions
and the balanced chemical equation for
the galvanic cells constructed from the following pairs of redox couples. Determine the standard cell potential for each cell.
a) Pb/Pb
2+ and Zn/Zn
2+^
Get the reduction half-reactions and their st
andard reduction potentials from Table 11.1
Zn
2+ + 2e
1-U^
Zn
oE
= -0.76 V
Pb
2+ + 2e
1-^ U
Pb
oE
= -0.13 V
The oxidation half-reaction is the one at more
negative potential, so
Zn is oxidized, and
Pb
2+ is reduced in the cell. Both half-reacti
ons involve two electrons, so the balanced
chemical equation is the sum of the following two reactions: Zn
U
Zn
2+ + 2e
1-^
Anode (oxidation) half-reaction
Pb
2+ + 2e
1-^ U
Pb
Cathode (reduction) half-reaction
Zn + Pb
2+^
→
Zn
2+ + Pb Net chemical equation
oE
cell
(^) =
o (^) E
cathode
- E
o anode
= -0.13 - (-0.76) = 0.63 V
o (^) E
cell
is positive, so the reaction is extensive.
b) Ni
2+/Ni and Ag
1+/Ag
The two relevant half-reactions and t
heir standard reduction potentials are
Ni
2+ + 2e
1-^ U
Ni
oE
= -0.23 V
Ag
1+ + e
1-U^
Ag
oE
= +0.80 V
Reverse the half-reaction at mo
re negative potential to obtain the oxidation and multiply
the Ag
1+/Ag half-reaction by 2 to make t
he number of electrons gained by Ag
1+ equal to
the number lost by the Ni. The balanced chemic
al equation for the cell is the sum of the
two reactions. Ni
U
Ni
2+ + 2e
1-^
Anode (oxidation) half-reaction
2Ag
1+ + 2e
1-^ U
2Ag
Cathode (reduction) half-reaction
Ni + 2Ag
1+^
→
Ni
2+ + 2Ag Net chemical equation
Standard reduction potentials indicate the free en
ergy of the electron(s), so multiplying a
half-reaction by some number does not
affect its standard reduction potential
. Thus,
multiplying the Ag
1+/Ag half-reaction by 2 does not ch
ange the potential at which the
couple is at equilibriu
m. The cell potential is
oE
cell
=
oE
cathode
- E
oanode
= +0.80 - (-0.23) = 1.03 V