H
F
I
F
I
H
Dc= 1.8Dc= 1.3Dc= 0.5I
Dc I
=0a)b)c)d)dd+-HCl Figure 5.3 Charge distribution in some covalent bonds Red is used to show regions that carry negative charge, while blue is used for regions that carry positive charge. The dipole arrow is used to show direction only.
Figure 5.2 Bond dipole in HCl The bond dipole is shown as the blue arrow. Cl is more electronegative than H, so the H-Cl bond dipole points from H to Cl. A line perpendicular to the a
rrow is placed at the positive endto produce a ‘+’ in the arrow.as the more electronegative atom becomes electron rich and the less electronegative atom becomes electron poor. The result is that negative charge is produced on the more electronegative atom and positive charge on the less electronegative atom. The charge that is produced in a covalent bond is only a part of what it would be if the bond were ionic, so it is said to be a
partial charge,
which is represented with a
(delta). Thus, a covalent δ
bond involving atoms of different electronegativities has two electrical poles (
- and δ
+) δ
and is said to have a
bond
di
pole. The bond dipole is represented by a vector pointing
from the center of positive charge toward the
center of negative charge with a line drawn
through the positive end to make a ‘+’ as shown in Figure 5.2. The strength of a bond dipole (the polarity of the bond) increases as the electronegativity difference (
Δχ
) between
the bound atoms increases. Consider the four molecules in Figure 5.3. Figure 5.3a
: The two iodine atoms in Ihave identical electronegativities, so 2Δχ= 0 andδ = 0.The atoms attract the bonding electrons equally and form a purely covalent bond. Thereis no charge separation in purely covalent bonds (no red and blue regions in the figure).
Figure 5.3b: Iodine (χ = 2.7) is more electronegative than hydrogen (χ = 2.2), so the bondingelectrons in an H-I bond are pulled away from the hydrogen and toward the iodine atom. As a result, the iodine atom is electron richand has a partial negative charge, while theless electronegative hydrogen atom develops a partial positive charge. H-I has a bond dipole, but the bond is not very polar (as indicated by the very pale shading) becauseΔχis only 0.5. The bond dipole in HI points from H to I.
Figure 5.3c: Δχ= 1.3 for an I-F bond, so it is more polar than an H-I bond (as indicated by thedarker shading). Fluorine is the more electronegative atom in this bond, so the bond dipole points toward fluorine.
Figure 5.3d: Δχ= 1.8 for an H-F bond, so the H-F bond is more polar than an I-F bond (darkershading). The bond dipole points from H to F.
The bond between two atoms is purely covalent if their electronegativities are
identical, but it becomes increasingly polar asthe difference in their electronegativities
increases. At a sufficiently large
difference, the bond is so polar that it is considered to be
an ionic bond. The nature of the bond is sometimes given in terms of its
percent ionic
character
. The more polar a bond is, the higher is
its percent ionic character. An F-F
bond (
Δχ
= 0) is purely covalent and has no ionic character (0% ionic), while a RbF bond
(Δχ
= 3.2) is 90% ionic, which means that the charge (
) on the rubidium is +0.9. δ
As shown in Figure 5.4, the change from covalent to ionic is gradual with no distinct
line between the two bond types. In the following discussion, we will assume that a bond
is covalent if it is less than 5% ionic, that a bond is polar covalent if it is between 5 and
Chapter 5 The Covalent Bond© byNorthCarolinaStateUniversity