F > 0 dx > 0 dK > 0
F < 0 dx < 0 dK > 0
F > 0 dx < 0 dK < 0
F < 0 dx > 0 dK < 0
This looks exactly like the rule for determining the sign of a product,
and we can easily show using the chain rule that this is indeed a
multiplicative relationship:
dK=
dK
dv
dv
dt
dt
dx
dx [chain rule]
= (mv)(a)(1/v) dx
=madx
=F dx [Newton’s second law]
We can verify that force multiplied by distance has units of energy:
N·m =
kg·m/s
s
×m
= kg·m^2 /s^2
= J
A TV picture tube example 30
.At the back of a typical TV’s picture tube, electrical forces accel-
erate each electron to an energy of 5× 10 −^16 J over a distance
of about 1 cm. How much force is applied to a single electron?
(Assume the force is constant.) What is the corresponding accel-
eration?
.Integrating
dK=Fdx,
we find
Kf−Ki=F(xf−xi)
or
∆K=F∆x.
The force is
F=∆K/∆x
=
5 × 10 −^16 J
0.01 m
= 5× 10 −^14 N.
Section 3.2 Force in one dimension 165