Simple Nature - Light and Matter

(Martin Jones) #1
f/The field−yxˆ.

g/Example 14.

h/Example 15.

by evaluating the field at the midpoints of its sides,

x=s/ 2 y= 0 F= (s/2)yˆ s 1 ·F=s^2 / 2
x= 0 y=s/ 2 F= 0 s 2 ·F= 0
x=−s/ 2 y= 0 F=−(s/2)yˆ s 3 ·F=s^2 / 2
x= 0 y=−s/ 2 F= 0 s 4 ·F= 0,

which gives a circulation of s^2 , and a curl with a magnitude of
s^2 /area =s^2 /s^2 = 1. By the right-hand rule, the curl points out of
the page, i.e., along the positivezaxis, so we have


curlxyˆ=ˆz.

Now consider the field−yxˆ, shown in figure f. This is the same
as the previous field, but with your book rotated by 90 degrees about
thezaxis. Rotating the result of the first calculation,zˆ, about the
zaxis doesn’t change it, so the curl of this field is alsoˆz.

Scaling
When you’re taking an ordinary derivative, you have the rule

d
dx

[cf(x)] =c
d
dx

f(x).

In other words, multiplying a function by a constant results in a
derivative that is multiplied by that constant. The curl is a kind of
derivative operator, and the same is true for a curl.
Multiplying the field by− 1. example 14
.What is the curl of the field−xˆyat the origin?
.Using the scaling property just discussed, we can make this into
a curl that we’ve already calculated:

curl (−xyˆ) =−curl (xˆy)
=−ˆz

This is in agreement with the right-hand rule.

The curl is additive.
We have only calculated each field’s curl at the origin, but each
of these fields actually has the same curl everywhere. In example
14, for instance, it is obvious that the curl is constant along any
vertical line. But even if we move along thexaxis, there is still an
imbalance between the torques on the left and right sides of the curl-
meter. More formally, suppose we start from the origin and move
to the left by one unit. We find ourselves in a region where the field

Section 11.4 Ampere’s law in differential form (optional)` 707
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