Introduction to Probability and Statistics for Engineers and Scientists

(Sean Pound) #1

4.7Covariance and Variance of Sums of Random Variables 123


Proof

Cov



∑n

i= 1

Xi,

∑m

j= 1

Yj



=

∑n

i= 1

Cov


Xi,

∑m

j= 1

Yj


 from Equation 4.7.5

=

∑n

i= 1

Cov



∑m

j= 1

Yj,Xi


 by the symmetry property Equation 4.7.2

=

∑n

i= 1

∑m

j= 1

Cov(Yj,Xi) again from Equation 4.7.5

and the result now follows by again applying the property Equation 4.7.2. 


Using Equation 4.7.3 gives rise to the following formula for the variance of a sum of
random variables.


Corollary 4.7.3

Var

( n

i= 1

Xi

)
=

∑n

i= 1

Var(Xi)+

∑n

i= 1

∑n

j= 1
j=i

Cov(Xi,Xj)

Proof

The proof follows directly from Proposition 4.7.2 upon settingm=n, andYj=Xjfor
j=1,...,n. 


In the case ofn=2, Corollary 4.7.3 yields that

Var(X+Y)=Var(X)+Var(Y)+Cov(X,Y)+Cov(Y,X)

or, using Equation 4.7.2,


Var(X+Y)=Var(X)+Var(Y)+2Cov(X,Y) (4.7.6)

Theorem 4.7.4

IfXandYare independent random variables, then


Cov(X,Y)= 0
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