10.3One-Way Analysis of Variance 447
p-Values in a One-way ANOVAStartQuit1
2
3
4
5Sample 1
220
251
226
246
260244
235
232
242
225The value of the f-statistic is 2.6009
The p-value is 0.1124SSW
M*(N−1)= 165.9667SSB
M− 1 = 431.6667Sample 2 Sample 3
252
272
250
238
256FIGURE 10.1
The following represents the total mileages obtained by the different motors:
Gas 1: 220 251 226 246 260
Gas 2: 244 235 232 242 225
Gas 3: 252 272 250 238 256Test the hypothesis that the average mileage obtained is not affected by the type of gas
used. Use the 5 percent level of significance.
SOLUTION We run Program 10.3 to obtain the results shown in Figure 10.1. Since the
p-value is greater than .05, the null hypothesis that the mean mileage is the same for all 3
brands of gasoline cannot be rejected. ■
The following algebraic identity, called the sum of squares identity, is useful when
doing the computations by hand.
The Sum of Squares Identity∑mi= 1∑nj= 1Xij^2 =nmX..^2 +SSb+SSW