Introduction to Probability and Statistics for Engineers and Scientists

(Sean Pound) #1

14.5The Weibull Distribution in Life Testing 601


Weibull (1, 0.5)

x

012345

1.2
1.0
0.8
0.6
0.4
0.2
0.0

Weibull (1, 2)

x

012345

1.0
0.8
0.6
0.4
0.2
0.0

Weibull (1, 1)

x

012345

1.0
0.8
0.6
0.4
0.2
0.0

Weibull (1, 3)

x

012345

1.2
1.0
0.8
0.6
0.4
0.2
0.0

FIGURE 14.2 Weibull density functions.


and



∂α

logf(x 1 ,...,xn)=

n
α


∑n

i= 1

xβi


∂β

logf(x 1 ,...,xn)=

n
β

+

∑n

i= 1

logxi−α

∑n

i= 1

xiβlogxi

Equating to zero shows that the maximum likelihood estimatesαˆandβˆare the solutions of


n
αˆ

=

∑n

i= 1

x
βˆ
i

n
βˆ

+

∑n

i= 1

logxi=ˆα

∑n

i= 1

x
βˆ
i logxi
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