14.5The Weibull Distribution in Life Testing 603
could conclude that
yi≈βlogx(i)+logα, i=1,...,n (14.5.4)We could then chooseαandβto minimize the sum of the squared errors — that is,α
andβare chosen to
minimize
α,β∑ni= 1(yi−βlogx(i)−logα)^2Indeed, using Proposition 9.2.1 we obtain that the preceding minimum is attained when
α=ˆα,β=βˆwhere
βˆ=∑ni= 1yilogx(i)−nlogxy ̄∑ni= 1(logx(i))^2 −n(logx)^2logαˆ= ̄y−βlogxwhere
logx=∑ni= 1(logx(i))/
n, y ̄=∑ni= 1yi/
nTo utilize the foregoing, we need to be able to determine valuesyithat approximate log
log(1/[ 1 −F(x(i))]=log[−log(1−F(x(i)))),i=1,...,n. We now present two different
methods for doing this.
Method 1:This method uses the fact that
E[F(X(i))]=i
(n+1)(14.5.5)and then approximatesF(x(i))byE[F(X(i))]. Thus, this method calls for using
yi=log{−log(1−E[F(X(i))])} (14.5.6)=log{
−log(
1 −i
(n+1))}=log{
−log(
n+ 1 −i
n+ 1)}