The energy–momentum tensor 15The idea here is that the changes experienced by an observer moving with the
fluid are inevitably a mixture of temporal and spatial changes. This two-part
derivative arises automatically in the relativistic formulation through the 4-vector
dot productUμ∂μ, which arises from the 4-divergence of an energy–momentum
tensor containing a term∝UμUν.
The equations that result from unpackingTμν,ν =0inthiswayhavea
familiar physical interpretation. Theμ= 1 , 2 ,3 components ofT,νμν=0give
the relativistic generalization ofEuler’s equationfor momentum conservation in
fluid mechanics (not to be confused with Euler’s equation in variational calculus):
d
dtv=−1
γ^2 (ρ+p/c^2 )(∇p+ ̇pv/c^2 ),and theμ=0 component gives a generalization of conservation of energy:
d
dt[γ^2 (ρ+p/c^2 )]= ̇p/c^2 −γ^2 (ρ+p/c^2 )∇·v,where p ̇ ≡ ∂p/∂t. The meaning of this equation may be made clearer by
introducing one further conservation law: particle number. This is governed by a
4-current having zero 4-divergence:
d
dxμJμ= 0 , Jμ≡nUμ=γn(c,v).If we now introduce therelativistic enthalpyw = ρ+p/c^2 , then energy
conservation becomes
d
dt
(γwn)
=
p ̇
γnc^2.
Thus,insteadyflow,γ×(enthalpy per particle)is constant.
A very useful general procedure can be illustrated bylinearizingthe fluid
equations. Consider a small perturbation about each quantity (ρ→ρ+δρetc)
and subtract the unperturbed equations to yield equations for the perturbations
valid to first order. This means that any higher-order term such asδv·∇δρis set
equal to zero. If we take the initial state to have constant density and pressure and
zero velocity, then the resulting equations are simple:
∂
∂tδv=−1
ρ+p/c^2∇δp∂
∂tδρ=−(ρ+p/c^2 )∇·δv.Now eliminate the perturbed velocity (via the divergence of the first of these
equations minus the time derivative of the second) to yield the wave equation:
∇^2 δρ−(
∂ρ
∂p)
∂^2 δρ
∂t^2