and if her estimate of dis correct, then she has a probability of .43 of actually rejecting
if it is false to the extent she expects (and a probability of .57 of making a Type II
error).
We next turn the question around and ask how many subjects would be needed for
power 5 .80. From Appendix Power, this would require d52.80.
nrefers to the number of subjects per sample, so for power 5 .80, we need 63 subjects per
sample for a total of 126 subjects.
Unequal Sample Sizes
We just dealt with the case in which However, experiments often have two
samples of different sizes. This obviously presents difficulties when we try to solve for d,
since we need one value for n. What value can we use?
With reasonably large and nearly equal samples, a conservative approximation can be
obtained by letting nequal the smaller of and. This is not satisfactory, however, if the
sample sizes are small or if the two ns are quite different. For those cases we need a more
exact solution.
One seemingly reasonable (but incorrect) procedure would be to set nequal to the
arithmetic mean of and. This method would weight the two samples equally, how-
ever, when in fact we know that the variance of means is proportional not to n, but to 1/n.
The measure that takes this relationship into account is not the arithmetic mean but the har-
monic mean. The harmonic mean ( )of knumbers ( ) is defined as
Thus for two samples sizes ( and ),
we can then use in our calculation of d.
In Chapter 7 we saw an example from Aronson et al. (1998) in which they showed that
they could produce a substantial decrement in the math scores of white males just by re-
minding them that Asian students tend to do better on math exams. This is an interesting
nh
nh=
2
1
n 1
1
1
n 2
=
2 n 1 n 2
n 11 n 2
n 1 n 2
Xh=
k
a
1
Xi
Xh X 1 , X 2 ,... , Xk
n 1 n 2
n 1 n 2
n 1 =n 2 =n.
=62.72
= 2 a
2.80
0.50
b
2
=2(5.6)^2
n= 2 a
d
d
b
2
a
d
d
b
2
=
n
2
d
d
=
A
n
2
d=d
A
n
2
H 0
234 Chapter 8 Power
harmonic
mean ( )Xh