Optimal stopping
As we have already seen ifT=n+ 1 ,thenSn(T)=fmaxknξkag.
Now letT=n+2 that is two periods are still ahead. We must show that
Sn=Sn(T)Sn(T+^1 ).
Vn$max
maxknξk,E(Vn 1 ++^1 j Fr n)
=
=max
0
@max
kn
ξk,
E
max
maxkn+ 1 ξk,E(Vn+ 12 +jFrn+^1 )
j Fn
1 +r
1
A.
As
max
kn+ 1
ξkmax
kn
ξka
using the induction hypothesis that if one periods left then the
fxjxagis the stopping region
max
kmaxn+ 1 ξk,E(Vn+^2 j Fn+^1 )
1 +r
=kmaxn+ 1 ξk.