Calculus of variations
First we solve the equation2 yu(y) d
dyu(y)+u^2 (y)= 0.Ifu(y)=0 theny^0 (x)=0 theny(x)is a constant which is not a
solution. We can simplify byu2 ydu
dy+u = 0 ,^1
udu= ^1
2 ydylnu = ^1
2lny+cu = cp^1
jyj,y^0 =cp^1
jyj