0195136047.pdf

174 TIME-DEPENDENT CIRCUIT ANALYSIS

% Element parameters

ZL1 = 100j;

ZL2 = 100j;

ZC1 = -50j;

ZC2 = -50j;

% I = inverse (Z) *V

I = inv ([RS+ZC1+ZL2 -ZL2 -ZC1;

-ZL2 ZL2+ZC2+RL -ZC2;

-ZC1 -ZC2 ZC1+ZC2+ZL1]) * [VS 0 0]’;

% Mesh Currents

IA = I(1)

IB = I(2)

IC = I(3)

% Answers

KI + RL*IB/VS

ZIN + VS/IA-RS

IA + 0.0100 - 0.0300i

IB = -0.0100 + 0.0300i

IC=0-0.1000i

K = -0.0500 + 0.1500i

ZIN = 5.0000e+01 + 3.0000e+02i

EXAMPLE 3.6.2

Consider the circuit shown in Figure E3.6.2 in thet-domain as well as in thes-domain. Formulate

thes-domain nodal equations and use MATLAB to solve forVA(s)andVB(s).

iS(t)

L

RRC

(a)

IS(s) CvC(0)

VA(s)

at node A

VB(s)

at node B

Ls

Cs

1

(b)

s

iL(0)

Figure E3.6.2(a)t-domain.(b)s-domain.

Solution

At nodeA:

VA(s)

R

+

VA(s)−VB(s)

Ls

−IS(s)+

iL( 0 )

s

= 0