354 SEMICONDUCTOR DEVICES
−VZVZ
Dr DfRZRZiv10
i Break pointsvvi(a) (c)Ideal
diodeIdeal
diode(b)+Figure 7.2.7Zener diode.(a)Device symbol.(b)Linearizedi–vcurve.(c)Circuit model.EXAMPLE 7.2.6
Consider a simple zener voltage regulator with the circuit diagram shown in Figure E7.2.6(a).iZVS voutRSiout(a)+
−VS vout
VZRZRSiout(b)+
− +
−Figure E7.2.6(a) For a small reverse resistanceRZ<< RSandVS−RSiout>VZ, show thatvout∼=VZ.
(b) For values ofVS=25 V,RS= 100 ,VZ=20 V, andRZ= 4 , find:
(i) voutforiout=0 andiout=50 mA.
(ii) The corresponding values of the reverse currentiZthrough the zener diode.Solution(a) WhenVS−RSiout>VZ, the zener diode will be in reverse breakdown. The forward
diodeDfin our model of Figure 7.2.7(c) will be off while the reverse diodeDris on. The
equivalent circuit is then given by Figure E7.2.6(b).
Straightforward circuit analysis yields