Mass and volume flow rates
constant
v 1 ȡ 1 A 1 = v 2 ȡ 2 A 2
v 1 A 1 = v 2 A 2 = R
v = speed of fluid
ȡ = density of fluid
A = cross-sectional area of flow
Fluid is incompressible
R = volume flow rate
What is the speed of the ideal
fluid in the narrow part of the
pipe?
v 1 A 1 = v 2 A 2
v 2 = v 1 A 1 /A 2
v 2 = (2.0 m/s)(10 m^2 ) / 1.5 m^2
v 2 = 13 m/s
(^262) Copyright 2000-2007 Kinetic Books Co. Chapter 13