To answer this question, we begin by considering the number of nodes that must be
present on the vibrating string. The minimum number of nodes is two: There must be a
node at each end of the string because the string is attached to two fixed points. These
nodes might be the only two, but there may be intermediate nodes as well. Drawings of
standing waves with zero, one and two intermediate nodes are shown in Concept 1
below.Harmonics
for n = 1, 2, 3, ...
fn = nth harmonic, v = wave speed
Ȝn = wavelength of nth harmonic
L = string length
A tension of 417 N is applied to a
1.56 m string of mass 0.00133 kg.
What is the fundamental
frequency?
v = 699 m/s
ƒ 1 = (1)(699 m/s)/2(1.56 m)
ƒ 1 = 224 Hz
(^326) Copyright 2000-2007 Kinetic Books Co. Chapter 17