ABACUS - SQUARE ROOT OF
IMPERFECT SQUARESQUARE ROOT OF IMPERFECT SQUARE:
A. Example : 69744
a) Set the number in the abacus. In this number, the groups will be 6,97,44. In
dealing with five digit number, it is suggested to take the first three numbers
as a whole for finding the square root.
b) Take 697. Ask : what is the highest perfect square in 697. It is 676. Set the
square root 26 to the left of this number and subtract 676 from 697. You will
be left with 2144 in the abacus.
c) Double the square root of the first set 26 and set that in the left extreme of
the abacus. You have to set 52 at the left extreme.
d) Now consider the divisor 52 and the dividend 2144. How many 5’s are in 21?
There are 4. Set this 4 to the right of the square root of the first two digits.
You will get 524 at the left extreme. Now multiply 4×524 and subtract the
value from 2144. You will get the remainder 48.
e) Now you have to go for your decimal part of the square root. Add one zero to
the dividend 48 and make it 480.
f) For divisor, you can double the present square root 264. If you take 528
itself, the number will not affect the value because we are dealing only with
the decimals. Since 480 is less than 528, your first decimal digit of the square
root will be 0. Now add one more zero to the dividend. Now you get 4800.