Final Cover - For Printing

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Out of the 63 combinations of the Braille cells, 26 combinations have already been

used to indicate the open Braille alphabets. Identify the remaining 37 combinations,

by going through the mirror images of each letter.

Mirror image of letter (a) is dot 4

Dot 4 has not been used so far and therefore, reverse of ‘a’ becomes the 27th

combination. Similarly, reverse of letter ‘b’ is dots 4 and 5 ( ) which has not

appeared so far and therefore, it becomes the 28th combination. However, the reverse

of letter ‘c’ indicates ‘c’ only and therefore, it doesn’t make another combination.

Similarly, reverse of letter ‘d’ is letter ‘f’ and therefore, we are still at the 28th

combination. Similar are the cases with letters (e, f, g, h, i, and j). The reverse of

letter ‘k’ is dots 4 and 6 ( ) and this combination has not been used so far

and therefore, it becomes the 29th combination. Find out the 15 combinations which

are not repeated. Therefore, by analysing the mirror images of the alphabets, you

get additional 15 combinations, which will make the total combinations so far as 41.

Look for the remaining 22 combinations.

Step 2 : In Nemeth code, the letters a,b,c,d,e,f,g,h,i, and j, when written in the lower cell
of the Braille cells become numbers 1, 2, 3, 4, 5, 6, 7, 8, 9, and 0 respectively
if preceded by the number sign ( ) (dots 3, 4, 5 and 6). The number cells and
their mirror images are as follows:

••..

••

••

-.
••
.•
-.
••

••..

••

••.

• ••


• ..


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