Principles of Mathematics in Operations Research

214 Solutions

(c) Integrator:

B(n,k) =

Utii

0

0

0

0

0

0

0

0

0

0

mir"

0

0

0

0

0

0 r

0

0

0

0

I

n"

After permuting some rows, we have

0

PB(n,k) =

n?=i<

o o n5^ o

0 0

0 0

0

0

0

0

0

Hj = n~fc+1 ^

[PB(n,k)} \UB]

0

-» In-k+1

0

where

UE

I\LI<

0

0

0

0

0

0

0

0

rtfi'-

1

*

0

0

0

0

0 r

0

0

0

1

Thus,

Furthermore,

K(B) = M.n-k+1 =K(BT).

M(BT) = Rk and M{B) = {6}.