Solutions 247D=(0,8,10)x3 A,V,Y, V72>Fig. S.12. Exercise 8.1: Primal and dual polyhedraThus, S3 enters.
B-iNss =10-1
01 0
00 10
0
-1=1
0
-1•Si
X3
x 2Thus, «i leaves.
New partition is XB — (sz,X3,X2)T, x?j = (xi,S2,s)T. Then,
£ =OOll
0 10
-1 0 1J5-^1"10
01
1 0-1"
0
0