Principles of Mathematics in Operations Research

Solutions 283

V^2 /

0.00000398

0.00000002

48.00005 0

0 24

Then,

x

w =

0.00000398"

0.00000002

Finally, V/ (

• 
  
  
  
  • 1
    48.00005
  
  
  
  

1.98 x 10"^12 '

n )-

1

24.

0.0001910000]

0.000000364 J ~

'9.5 x 10"^11 '

0 , which is

r^n" J/ L " J r ^ « n

Thus, x* =

0 =• v/(x*) = e, v

2

/(x*) =

40 U

0 24

1.98 x 10"^12

0

. Since V^2 /(x*) is

diagonal with positive entries, it is positive definite. Therefore, x = 6 is a
local minimizer with f(x) = 0.