46 3 Orthogonality
w
Fig. 3.8. Least norm squared solution: (ATA) is not invertible and A^ = QiE'Qj
Table 3.1. How to solve Ax = b, where A G Rmx"
Case
b e -£(4)
b e M(AT)
b <jL 11(A)
bgAf(A)
Subcase
r=n=m
r=m < n
A=[B\N]
r=m
[A\\b
B\N
o
r <
A^ -
< n
6'
0
m
I\N~\
O \
(ATA):
invertible
(ATA):
not
invertible
Solution
x=A~^1 b
XB =
B_16-
B~^1 Nxn
XB =
B-'b-
B^NXn
many
x=A*b
many
x=A*b
min.norm
Type
Exact
unique
Exact
many
Exact
many
Trivial
Least
Squares
Unique
Least
Squares
Least
Norm
Squares
Special Forms
A=LU => Lc=b,Ux=c
A=QR => Rx=QTb
A = QtEQl =»
x=Q 2 Z-xQlb
B=LU => Lc=b,UxB=c
B=QR => RxB=QTb
B=Q-,EQl =>
xB=Q2S-^1 Qjb
B=LU =• Lc=b,UxB-c
B=QR => RxB=QTb
B=Q 1 EQ 2 r =>
xB=Q2Z~^1 QTb
T
x=a
VaG
' -N'
I
M.n~r
)
A=QR => Rx=QTb
A = QxEQl =>
x=Q 2 E-lQjb
A^QiEQZ =*
x=Q 2 E1iQjb
Inverse
A^A-^1
A^B-^1
A* « B-^1
none
A*=
(ATA)~^1 AT
A*=
Q 2 E^Ql