404 CHAPTER 11 Elimination Reactions of Alkyl Halides • Competition Between Substitution and EliminationAlexander M. Zaitsev (1841–1910)
was born in Kazan, Russia. The
German transliteration, Saytzeff, is
sometimes used for his family name.
He received a Ph.D. from the
University of Leipzig in 1866.
He was a professor of chemistry first
at the University of Kazan and
later at the University of Kiev.The most stable alkene is generally (but
not always) the most substituted
alkene.to two hydrogens. According to Zaitsev’s rule, the more substituted alkene will be
the one formed by removing a proton from the -carbon that is bonded to two hydro-
gens, rather than from the -carbon that is bonded to three hydrogens. Therefore,
2-pentene (a disubstituted alkene) is the major product, and 1-pentene (a monosubsti-
tuted alkene) is the minor product.Because elimination from a tertiary alkyl halide typically leads to a more substituted
alkene than does elimination from a secondary alkyl halide, and elimination from a sec-
ondary alkyl halide generally leads to a more substituted alkene than does elimination
from a primary alkyl halide, the relative reactivities of alkyl halides in an E2 reaction
are as follows:Keep in mind that the major product of an E2 reaction is the more stable alkene,and
Zaitsev’s rule is just a shortcut to determine which of the possible alkene products is
the more substituted alkene. The more substituted alkene is not, however, always the
more stable alkene. In the following reactions, the conjugated alkene is the more sta-
ble alkene even though it is not the most substituted alkene. The major product of each
reaction is, therefore, the conjugated alkene because, being more stable, it is more
easily formed.three alkyl substituents two alkyl substituents one alkyl substituentRCH RCH CHR RCH CH 2RCH 2 CRCRRRBrRCH 2 CHRBrRCH 2 CH 2 Brtertiary alkyl halide > secondary alkyl halide > primary alkyl haliderelative reactivities of alkyl halides in an E2 reactionbbZaitsev’s rule leads to the most
substituted alkene.CH 3 CH 2 CH 2 CHCH 3 + HO− CH 3 CH 2 CH CHCH 3 + CH 3 CH 2 CH 2 CH CH 2Cl2 -hydrogens2-pentene
67%
(mixture of E and Z)2-chloropentane 1-pentene
33%3 -hydrogens disubstituted monosubstitutedCHCH 2 CHCHCH 3HO−
CH 2 CH 2 CHCH CHCHCH 3 + CH 2 CHCH 2 CH CCH 3 + H 2 O + Cl−ClCH 3 CH 3 CH 34-chloro-5-methyl-1-hexene5-methyl-1,3-hexadiene
a conjugated diene
major product5-methyl-1,4-hexadiene
an isolated diene
minor productCH 2 CHCHCH 3Br
2-bromo-3-methyl-
1-phenylbutaneCH 3CH CHCHCH 3 +3-methyl-1-phenyl-1-butene
the double bond is
conjugated with the
benzene ring
major productCH 3CH 2 CH CCH 3 + H 2 O + Br−3-methyl-1-phenyl-2-butene
the double bond is
not conjugated with the
benzene ring
minor productCH 3
HO−Tutorial:
E2 Elimination regiochemistryBRUI11-400_436r3 26-03-2003 10:20 AM Page 404