Section 15.4 Some Chemical Consequences of Aromaticity 599Similarly, furan and thiophene are stable aromatic compounds. Both the oxygen in
the former and the sulfur in the latter are hybridized and have one lone pair in an
orbital. The second lone pair is in a porbital that overlaps the porbitals of adjacent
carbons, forming a bond. Thus, they are electrons.
Quinoline, indole, imidazole, purine, and pyrimidine are other examples of hetero-
cyclic aromatic compounds. The heterocyclic compounds discussed in this section are
examined in greater detail in Chapter 21.
PROBLEM 5In what orbitals are the electrons represented as lone pairs when drawing the structures of
quinoline, indole, imidazole, purine, and pyrimidine?PROBLEM 6Answer the following questions by examining the electrostatic potential maps on p. 598:
a. Why is the bottom part of the electrostatic potential map of pyrrole blue?
b. Why is the bottom part of the electrostatic potential map of pyridine red?
c. Why is the center of the electrostatic potential map of benzene more red than the
center of the electrostatic potential map of pyridine?15.4 Some Chemical Consequences of Aromaticity
The of cyclopentadiene is 15, which is extraordinarily acidic for a hydrogen that
is bonded to an hybridized carbon. Ethane, for example, has a of 50.
CH 3 CH 3 +HHHCH 3 CH 2 H++ H+cyclopentadieneethane ethyl anioncyclopentadienyl
anion
−−pKa = 50pKa = 15sp^3 pKapKaNNN
quinoline indole imidazole purine pyrimidineN
HN NHNNNNHresonance contributors of furanOO OO O−−
++++− −p psp^2
sp^2N H Oorbital structure of pyrrolethese
electrons
are in a
p orbitalthese
electrons
are in a
p orbitalorbital structure of furanthese
electrons are
in an sp^2 orbital
perpendicular
to the p orbitals