Section 19.16 Intramolecular Condensation and Addition Reactions 815
to completion by carrying out the reaction with enough base to remove a proton from
the of the ester product. When the reaction is over, acid is added to
reprotonate the condensation product.
PROBLEM 28
Write the mechanism for the base-catalyzed formation of a cyclic ester from a
1,7-diester.
Intramolecular Aldol Additions
Because a 1,4-diketone has two different sets of two different intramol-
ecular addition products can potentially form—one with a five-membered ring, the
other with a three-membered ring. The greater stability of five- and six-membered
rings causes them to be formed preferentially (Section 2.11). In fact, the five-
membered ring product is the only product formed from the intramolecular aldol ad-
dition of a 1,4-diketone.
The intramolecular aldol addition of a 1,6-diketone potentially can lead to either a
seven- or a five-membered ring product. Again, the more stable product—the one with
the five-membered ring—is the only product of the reaction.
1,5-Diketones and 1,7-diketones undergo intramolecular aldol additions to form
six-membered ring products.
a-hydrogens,
b-keto
a-carbon b-keto
CH 2 CH 2 COCH 3
CH 2 COCH 3
CH 2
O O O
O
O
CH 3 O−
mechanism for the Dieckmann condensation
CH 2 CHCOCH 3
CH 2 COCH 3
CH 2
O
OCH+ 3 OH
+ CH 3 O−
COCH 3 COCH 3
O
OCH 3
−
−
CH 3 CCH 2 CH 2 CCH 2
C CH 3
OO
CH 3 CCH 2 CH 2 CCH 3
2,5-hexanedione
a 1,4-diketone
OO
O
H 2 O
H 2 O CH
3
O H 2 O
−O
CH 3
O
− HO
HO−
HO−
CH 3 CCH 2 CHCCH 3
OO
CH 3
−O H 2 O C CH 3
O
− CH 3
HO
not formed
CH 3 CCH 2 CH 2 CH 2 CH 2 CCH 3
2,7-octanedione
a 1,6-diketone
OO
H 2 O
H 2 O
HO−
HO−
CH 3 CCH 2 CH 2 CH 2 CHCCH 3
OO
CH 3
H 2 O
−O
−
CCH 3
O
CH 3
CCH 3
O
CH 3 CCH 2 CH 2 CH 2 CH 2 CCH 2
OO
HO
H 2 O
−
O
CH 3
O−
O
CH 3
OH
not formed