If the leaving groups at C-2 and C-4 are different, the incoming nucleophile will
preferentially substitute for the weaker base (the better leaving group).
PROBLEM 19
Compare the mechanisms of the following reactions:
PROBLEM 20
a. Propose a mechanism for the following reaction:
b. What other product is formed?
∆
N N O
H
KOH/H 2 O
+ −NH 2
N
Cl
+ Cl−
N
NH 2
+ −NH 2
Cl
+ Cl−
NH 2
N
Br
−NH
2
OCH 3
+
N
NH 2
Br−
OCH 3
+
∆
N
CH 3
CH 3 O−
Cl
+
N
CH 3
Cl−
OCH 3
+
∆
−N
2-position
most stable
most stable
N
−
− −
−
−
− −
−
N
N N
N
N
N N N
4-position
+ Y− 3-position
H
Y
H
Y
Y H
H
Y
H
Y
Y H
H
Y
H
Y
Y H
>Figure 21.3
Structures of the intermediates that
can be formed from the reaction of
a nucleophile with pyridine.
Section 21.10 Aromatic Six-Membered-Ring Heterocycles 905
Nucleophilic aromatic substitution of pyridine takes place at C-2 and C-4, because at-
tack at these positions leads to the most stable intermediate. Only when nucleophilic
attack occurs at these positions is a resonance contributor obtained that has the greatest
electron density on nitrogen, the most electronegative of the ring atoms (Figure 21.3).
slow
mechanism for nucleophilic aromatic substitution
fast
Y−
N
+
Z
Z−
N
+
N Z Y
Y
−
Pyridine undergoes nucleophilic
aromatic substitution at C-2 and C-4.
Pyridine is lessreactive than benzene to-
ward electrophilic aromatic substitution
and morereactive than benzene toward
nucleophilic aromatic substitution.