5.5 Determinants Associated with a Continued Fraction 205etc. These formulas lead to the following theorem.
Theorem 5.10.
fn−fn− 1 =(−1)n
(a 1 a 2 a 3 ···an)xn
+O(xn+1
),that is, the coefficients ofx
r
, 1 ≤r≤n− 1 , in the series expansion offnare identical to those in the expansion offn− 1.
Proof. Applying the recurrence relation (5.5.9),
Pn− 1 Qn−PnQn− 1 =Pn− 1 (Qn− 1 +anxQn− 2 )−(Pn− 1 +anxPn− 2 )Qn− 1=−anx(Pn− 2 Qn− 1 −Pn− 1 Qn− 2 )=an− 1 anx2
(Pn− 3 Qn− 2 −Pn− 2 Qn− 3 ).
.
.
=(−1)
n
(a 3 a 4 ···an)xn− 2
(P 1 Q 2 −P 2 Q 1 )=(−1)
n
(a 1 a 2 ···an)xn
(5.5.15)fn−fn− 1 =QnPn−
Qn− 1Pn− 1=
Pn− 1 Qn−PnQn− 1PnPn− 1=
(−1)
n
(a 1 a 2 ···an)x
nPnPn− 1. (5.5.16)
The theorem follows sincePn(x) is a polynomial withPn(0)=1.
Letfn(x)=∞
∑r=0crxr. (5.5.17)
From the third equation in (5.5.14),
c 0 =1,c 1 =−a 1 ,c 2 =a 1 (a 1 +a 2 ),c 3 =−a 1 (a2
1
+2a 1 a 2 +a2
2
+a 2 a 3 ),c 4 =a 1 (a2
1
a 2 +2a 1 a2
2
+a3
2
+2a2
2
a 3 +a2
1
a 3 +2a 1 a 2 a 3 +a 2 a2
3+a2
1
a 4 +a 1 a 2 a 4 +a 2 a 3 a 4 ), (5.5.18)etc. Solving these equations for thear,
a 1 =−|c 1 |,a 2 =∣
∣
∣
∣
c 0 c 1c 1 c 2∣
∣
∣
∣
|c 1 |