330 Appendix
=−
1
n+1
[
n+1
∑
r=0
(−1)
r
(
n+1
r
)
x
2 r
−
n+1
∑
r=0
(−1)
r
(
n+1
r
)
]
=−
1
n+1
[(1−x
2
)
n+1
−0]
S(0) =−
1
n+1
.
The result follows. It is applied withc= 1 in Section 4.10.4 on a particular
case of the Yamazaki–Hori determinant.
Example A.4. If
ψm=
∞
∑
r=1
r
m
x
r
,
then
∆
m
ψ 0 =xψm.
ψmis the generalized geometric series (Appendix A.6).
Proof.
(r−1)
m
=
m
∑
s=0
(−1)
m−s
(
m
s
)
r
s
.
Multiply both sides byx
r
and sum overrfrom 1 to∞. (In the sum on the
left, the first term is zero and can therefore be omitted.)
x
∞
∑
r=2
(r−1)
m
x
r− 1
=
∞
∑
r=1
x
r
m
∑
s=0
(−1)
m−s
(
m
s
)
r
s
,
x
∞
∑
s=1
s
m
x
s
=
m
∑
s=0
(−1)
m−s
(
m
s
) ∞
∑
r=1
r
s
x
r
,
xψm=
m
∑
s=0
(−1)
m−s
(
m
s
)
ψs
=∆
m
ψ 0.
This result is applied in Section 5.1.2 to prove Lawden’s theorem.
A.9 The Euler and Modified Euler Theorems on
Homogeneous Functions
The two theorems which follow concern two distinct kinds of homogeneity
of the function
f=f(x 0 ,x 1 ,x 2 ,...,xn). (A.9.1)