318 CHAPTER 9 Thin Plates
Fig.9.18
Determination of flange stress.
fromwhich
σcf=
Fc−^12 (σtcsinθcosθ+τm)twcc
Acf
(9.59)
whereFcistheforceinthecompressionflangeatWandAcfisthecross-sectionalareaofthecompression
flange.
Similarly,forthetensionflange,
σtf=
Ft+^12 (σttsinθcosθ+τm)twct
Atf
(9.60)
TheforcesFcandFtarefoundbyconsideringtheequilibriumofthebeamtotherightofWY(Fig.9.19).
Then,resolvingverticallyandnotingthatScr=τmtwd,
Sult=Fwsinθ+τmtwd+
∑
Wn (9.61)
ResolvinghorizontallyandnotingthatHcr=τmtw(b−cc−ct),
Fc−Ft=Fwcosθ−τmtw(b−cc−ct) (9.62)
TakingmomentsaboutO,wehave
Fc+Ft=
2
d
[
Sult
(
s+
b+cc−ct
2
)
+Mpt′−Mpc′
+Fwq−Mw−
∑
n
Wnzn
] (9.63)
whereW 1 toWnare external loads applied to the beam to the right of WY andMwis the bending
momentinthewebwhenithasbuckledandbecomeatensionfield,thatis,
Mw=
σmbbd^2
b