Introduction to Aircraft Structural Analysis (Elsevier Aerospace Engineering)

(nextflipdebug5) #1

534 CHAPTER 18 Combined Open and Closed Section Beams


Thetorsionalrigidityofthecompletesectionisthen


GJ= 5000 × 107 + 6 × 107 = 5006 × 107 Nmm^2

Inallunrestrainedtorsionproblems,thetorqueisrelatedtotherateoftwistbytheexpression


T=GJ


dz

Theangleoftwistperunitlengthisthereforegivenby



dz

=

T

GJ

=

10 × 106

5006 × 107

=0.0002rad/mm

SubstitutingforTinEq.(17.1)fromEq.(17.4),weobtaintheshearflowintheclosedsection.Thus,


qcl=

(GJ)cl
2 A


dz

=

5000 × 107

2 × 20000

×0.0002

fromwhich


qcl=250N/mm

Themaximumshearstressintheclosedsectionisthen250/1.5=166.7N/mm^2.
Intheopenportionofthesection,themaximumshearstressisobtaineddirectlyfromEq.(17.10)
andis


τmax,op= 25000 × 2 ×0.0002=10N/mm^2

Itcanbeseenfromtheabovethatintermsofstrengthandstiffness,theclosedportionofthewingsection
dominates.Thisdominancemaybeusedtodeterminethewarpingdistribution.Havingfirstfoundthe
positionofthecenteroftwist(theshearcenter),thewarpingoftheclosedportioniscalculatedusing
the method described in Section 17.1. The warping in the walls 13 and 34 is then determined using
Eq.(17.19),inwhichtheoriginforthesweptareaARistakenatthepoint1andthevalueofwarping
isthatpreviouslycalculatedfortheclosedportionat1.


Problems..............................................................................................


P.18.1 ThebeamsectionofExample18.1(seeFig.18.2)issubjectedtoabendingmomentinaverticalplaneof
20kNm.Calculatethemaximumdirectstressinthecrosssectionofthebeam.


Ans. 172.5N/mm^2.

P.18.2 AwingboxhasthecrosssectionshowndiagrammaticallyinFig.P.18.2andsupportsashearloadof100
kNinitsverticalplaneofsymmetry.Calculatetheshearstressatthemidpointoftheweb36ifthethicknessofall
wallsis2mm.


Ans. 89.7N/mm^2.
Free download pdf