2 78 Problems 8 Solutions on Thermodytomics d Statistical Mechanics
ii2
2m
and the kinetic energy of an electron is E = -k2. Combining, we get
At T = 0 K, the N electrons fill up the energy levels from zero to EF =
h"
-k>, i.e.,
2m
EF 2
N = D(&)d&= ;D(EF)EF
Jo
2m
(a) The specific heat is
where kB is Boltzmann's constant.
(b) The magnetic susceptibility is
where pB is the Bohr magneton.
(c), (d) The average kinetic energy is
2 3
ED(&)& = -D(EF)E; = -NEF ,
(Ek) = I"' 5 5
and the pressure on the walls of the box is
2105
fermions is confined to a volume V. Calculate
the zero temperature limit of (a) the chemical potential, (b) the average
An ideal gas of N spin