Problems and Solutions on Thermodynamics and Statistical Mechanics

(Ann) #1
Statistical Phyaca 281

4s
3

The volume of the nucleus is given by V = -RiA, Ro M 1.4 x
Please give the result in MeV.

cm.

(Chicago)

Solution:
In the momentum space,

4v
h3
dn = -4n-p2dp,

where n is the number density of neutrons.
The total number of neutrons is

A = 1 dn = 16n-V LPF $dP


where PF is the Fermi momentum.
The total kinetic energy of the neutrons is

Hence ,


The volume V can be expressed in two ways:

4n 3(2~)~ -3 h
V = -R3A = - pF A, (putting h z - = 1)
3O 16n 27r

giving p~ = R,' (2) 'I3, and

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