384 Problems €4 Solutionn on Thermodynamics €4 Statistical Mechanic8is its mean free path. As A = &, where n is the number density of argon
molecules, u is the cross section for scattering:
We have
P
RTn = - x NA = 1.01 x lo5 x 10 x 6.02 x 1023/(760 x 8.3 x 473)
= 2.04 x 1023m-3 ,
A M 1.7 x 10-14m ,w 413 m/s.
23 x 10-3
r FJ 4 x 10-~~ ,and hence
ax = -av x = - x2 w 3 x ~o-~A
Y cr2192
A gas consists of a mixture of two types of molecules, having molecular
masses MI and Mz grams, and number densities N1 and N2 molecules per
cubic centimeter, respectively.
The cross-section for collisions between the two different kinds of
molecules is given by AlVl,l, where A is a constant, and V12 is the rel-
ative velocity of the pair.
(a) Derive the average, over all pairs of dissimilar molecules, of the(b) How many collisions take place per cubic centimeter per second(UC, Berkeley)center-of-mass kinetic energy per pair.between dissimilar molecules?Solution:
According to the Maxwell distribution,